Optics
⏱ ~3-min readAceMark GuideWhat this topic is really about
Using the lens formula 1/f = 1/v - 1/u, we substitute f = 20 cm and v = 30 cm for a real image to get 1/20 = 1/30 - 1/u, which solves to u = -60 cm. Option A is incorrect because a 10 cm object distance is less than the focal length, which would produce a virtual image on the same side rather than a real image at 30 cm.
The critical angle for total internal reflection is determined by the ratio of the refractive indices of the two interfacing media, as described by Snell's law. Option A is incomplete because focusing only on wavelength ignores how both media must interact to determine the boundary's refractive properties.
See the mechanism
A plane mirror forms a virtual and erect image because the reflected light rays diverge and only appear to meet behind the mirror. A diagram for this topic isn't available yet — the worked example below walks the same reasoning step by step.
An exam-style question, fully explained
Image formed by a plane mirror is:
- Identify what the question tests: Image formed by a plane mirror is:.
- A plane mirror forms a virtual and erect image because the reflected light rays diverge and only appear to meet behind the mirror.
- Real images, like those in options A and C, require actual convergence of light rays, which cannot occur behind a flat reflecting surface.
Traps the examiner sets
- Option A is incorrect because a 10 cm object distance is less than the focal length, which would produce a virtual image on the same side rather than a real image at 30 cm.
Test your recall
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