Number system
⏱ ~3-min readAceMark GuideWhat this topic is really about
Any number that leaves a remainder of 3 when divided by 7 can be written as 7k + 3. Depending on whether k is even or odd, dividing this number by 14 will result in a remainder of either 3 or 10. Assuming the remainder can only be 3 overlooks the case where k is odd, leading to an incomplete answer.
The last digit of powers of 7 follows a repeating cycle of four: 7, 9, 3, and 1. Since the exponent 100 is perfectly divisible by 4, the last digit must be the fourth number in the cycle, which is 1. Option C is incorrect because 7 only appears when the exponent leaves a remainder of 1
See the mechanism
The greatest common divisor (GCD) is found by multiplying the lowest powers of common prime factors, which are 2^2 * 3 = 12. A diagram for this topic isn't available yet — the worked example below walks the same reasoning step by step.
An exam-style question, fully explained
GCD of 60 and 84:
- Identify what the question tests: GCD of 60 and 84:.
- The greatest common divisor (GCD) is found by multiplying the lowest powers of common prime factors, which are 2^2 * 3 = 12.
- Option A is incorrect because although 6 is a common divisor of both numbers, it is not the greatest common divisor.
Traps the examiner sets
- The greatest common divisor (GCD) is found by multiplying the lowest powers of common prime factors, which are 2^2 * 3 = 12.
- Option C is incorrect because 7 only appears when the exponent leaves a remainder of 1
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